How do you simplify $3 \sqrt{2} (2 \sqrt{-} 4) + \sqrt{2} (5 - \sqrt{2})$ $3sqrt2(2sqrt-4)+sqrt2(5-sqrt2)$ ?

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Answer 1 · 2017-05-05T13:02:57

$11 \sqrt{2} - 2$ $11sqrt2 - 2$

Before we begin tackling this problem, separate it into small chunks so that it is easier for us to handle.

$\sqrt{-} 4$ $sqrt-4$ does not exist as it is a negative surd(radical) so the problem looks like this.

$3 \sqrt{2} \cdot (2)$ $3sqrt2*(2)$ = $6 \sqrt{2}$ $6sqrt2$

$\sqrt{2} (5 - \sqrt{2})$ $sqrt2(5-sqrt2)$
Multiply it out and then simplify:

$5 \sqrt{2} - \sqrt{4}$ $5sqrt2-sqrt4$ = $5 \sqrt{2} - 2$ $5sqrt2 - 2$

Now add the two parts together which will give you the answer.

$6 \sqrt{2} + 5 \sqrt{2} - 2$ $6sqrt2 + 5sqrt2 - 2$

$= 11 \sqrt{2} - 2$ $= 11sqrt2 - 2$

How do you simplify 3√2(2√−4)+√2(5−√2)3sqrt2(2sqrt-4)+sqrt2(5-sqrt2)?