How do you simplify 3sqrt5 * sqrt53√5⋅√5? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer mason m Jun 3, 2016 1515 Explanation: Don't be confused by what 3sqrt53√5 means. It is just the multiplication of 33 and sqrt5√5, so 3sqrt5=3*sqrt53√5=3⋅√5. Therefore 3sqrt5*sqrt5=3*sqrt5*sqrt53√5⋅√5=3⋅√5⋅√5. We see that sqrt5*sqrt5=5√5⋅√5=5, so our expression becomes 3sqrt5*sqrt5=3*(sqrt5*sqrt5)=3*5=153√5⋅√5=3⋅(√5⋅√5)=3⋅5=15. Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 1405 views around the world You can reuse this answer Creative Commons License