How do you simplify $(3x^(-1/2)*3x^(1/2)y^(-1/3))/(3y^(-7/4))$ ?

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Answer 1 · 2017-05-13T17:03:47

$3y^(17/12)$

$(3x^(-1/2)*3x^(1/2)y^(-1/3))/(3y^(-7/4)$

$:.=(9x^(-1/2+1/2)*y^(-1/3))/(3y^(-7/4))$

$:.=(cancel9^color(blue)3x^0*y^(-1/3))/(cancel3^color(blue)1y^(-7/4))$

$:.=(3*1*y^(-1/3))/y^(-7/4)$

$:.=3/y^(-7/4+1/3)$

$:.=color(blue)(3/(y^(-17/12)$ $color(white)(aaaaaaaaaaaaa)$ $-7/4+1/3=(-21+4)/12=color(blue)(-17/12$

How do you simplify (3x^(-1/2)*3x^(1/2)y^(-1/3))/(3y^(-7/4))(3x^(-1/2)*3x^(1/2)y^(-1/3))/(3y^(-7/4))?