How do you simplify $(3x^ 2a - 4y az ^3a) ^2$ ?

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Answer 1 · 2017-07-15T10:41:15

$(3ax^2-4a^2yz^3)^2=9a^2x^4-24a^3x^2yz^3+16a^4y^2z^6$

First simplify how the expression is written:

$(3x^2a-4yaz^3a)^2$ is better written as $(3ax^2-4a^2yz^3)^2$

We write pronumerals in alphabetical order and collect them together.

Now use the FOIL (firsts, outers, inners, lasts) to multiply:

$(3ax^2-4a^2yz^3) = (3ax^2-4a^2yz^3)(3ax^2-4a^2yz^3)$
$=9a^2x^4-12a^3x^2yz^3-12a^3x^2yz^3+16a^4y^2z^6$
$=9a^2x^4-24a^3x^2yz^3+16a^4y^2z^6$

How do you simplify (3x^ 2a - 4y az ^3a) ^2 (3x^ 2a - 4y az ^3a) ^2 ?