How do you simplify $(3x+4)^3$ ?

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Answer 1 · 2017-10-09T11:56:50

$=27x^3+108x^2+144x+64$

Since

$(A+B)^3=A^3+3A^2B+3AB^2+B^3$

we get

$(3x+4)^3=(3x)^3+3(3x)^2*4+3(3x)*4^2+4^3=$

$=27x^3+108x^2+144x+64$

How do you simplify (3x+4)^3(3x+4)^3?