How do you simplify $3 x^{\frac{4}{3}} \cdot 2 x^{- \frac{7}{4}}$ $3x^(4/3) * 2x^(-7/4)$ ?

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Answer 1 · 2015-04-09T19:53:05

$3 x^{\frac{4}{3}} \cdot 2 x (- \frac{7}{4})$ $3x^(4/3)*2x(-7/4)$

$= (3) (2) \cdot (x^{\frac{4}{3}}) \cdot (x^{- \frac{7}{4}})$ $= (3)(2) * (x^(4/3)) * (x^(-7/4))$

$= (6) \cdot (x^{\frac{16}{12}}) \cdot (x^{- \frac{21}{12}})$ $=(6) * (x^(16/12)) * (x^(-21/12))$

$= 6 x^{- \frac{5}{12}}$ $= 6 x^(-5/12)$

How do you simplify 3x^(4/3) * 2x^(-7/4)3x43⋅2x−743x^(4/3) * 2x^(-7/4)?