How do you simplify $(3y^(1/4))/(4x^(-2/3)y^(3/2)*3y^(1/2))$ ?

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Answer 1 · 2017-05-18T17:14:07

$1/4. x^(2/3)/y^(7/4)$

Given, ${3y^(1/4)}/[4x^(-2/3)xxy^(3/2)xx3xxy^(1/2)]$

$rArr 3/(4xx3). y^(1/4) y^(-3/2)y^(-1/2)x^(2/3)$

$rArr 1/4. y^(1/4-3/2-1/2)x^(2/3)$

$rArr 1/4. y^(-7/4)x^(2/3)$

$rArr 1/4. x^(2/3)/y^(7/4)$

How do you simplify (3y^(1/4))/(4x^(-2/3)y^(3/2)*3y^(1/2))(3y^(1/4))/(4x^(-2/3)y^(3/2)*3y^(1/2))?