How do you simplify $4^(1/2)+9^(-1/2)$ ?

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Answer 1 · 2016-12-18T15:00:10

$2""1/3""or""7/3$

from the rules of indices we have

$x^(1/2)=sqrtx." "x^(-1/2)=1/sqrtx$

$4^(1/2)+9^(-1/2)=sqrt4+1/sqrt9$

$=2+1/3$

$=2""1/3=7/3$

How do you simplify 4^(1/2)+9^(-1/2)4^(1/2)+9^(-1/2)?