How do you simplify $49^{- \frac{1}{2}}$ $49^(-1/2)$ ?

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How do you simplify $49^{- \frac{1}{2}}$ $49^(-1/2)$ ?

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Answer 1 · 2017-01-31T09:40:40

$49^{- \frac{1}{2}} = {(7^{2})}^{- \frac{1}{2}} = 7^{(2) (- \frac{1}{2})} = 7^{- 1} = \frac{1}{7},$ $49^(-1/2)=(7^2)^(-1/2)=7^{(2)(-1/2)}=7^-1=1/7,$ or,

$49^{- \frac{1}{2}} = \frac{1}{49^{\frac{1}{2}}} = \frac{1}{\sqrt{49}} = \frac{1}{7}$ $49^(-1/2)=1/49^(1/2)=1/sqrt49=1/7$ .

Answer 2 · 2017-01-31T09:44:11

$\frac{1}{7}$ $1/7$

Explanation:

$49^{- \frac{1}{2}}$ $49^(-1/2)$

$:.(7^2)^(-1/2)$

$:=7^(2 xx -1/2)$

$:.=7^(-2/2)$

$:.=7^-1$

$:.=1/7$

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