How do you simplify $4sqrt(8x^8y^6z^5) times 4sqrt(2x^2y^2z)$ ?

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Answer 1 · 2018-03-27T13:53:29

$64x^5y^4z^3$

You can simplify each root as far as possible and then multiply the answers.

Or you can multiply the two roots together first and then find the square root of the product. I will follow the second option.

$4sqrt(8x^8y^6z^5) times 4sqrt(2x^2y^2z)$

$=4xx4sqrt(8x^8y^6z^5 times 2x^2y^2z)$

$= 16sqrt(16x^10y^8z^6)$

$= 16 xx4x^5y^4z^3" "larr$ divide the indices by $2$

$= 64x^5y^4z^3$

How do you simplify 4sqrt(8x^8y^6z^5) times 4sqrt(2x^2y^2z) 4sqrt(8x^8y^6z^5) times 4sqrt(2x^2y^2z) ?