How do you simplify $4 \sqrt{32} \cdot \sqrt{2}$ $4sqrt32*sqrt2$ ?

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Answer 1 · 2018-07-25T21:19:28

See a solution process below:

To simplify this expression use this rule for radicals:

$\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$ $sqrt(color(red)(a)) * sqrt(color(blue)(b)) = sqrt(color(red)(a) * color(blue)(b))$

$4 \sqrt{32} \cdot \sqrt{2} \Rightarrow$ $4sqrt(color(red)(32)) * sqrt(color(blue)(2)) =>$

$4 \sqrt{32 \cdot 2} \Rightarrow$ $4sqrt(color(red)(32) * color(blue)(2)) =>$

$4 \sqrt{64} \Rightarrow$ $4sqrt(64) =>$

$4 \cdot 8 \Rightarrow$ $4 * 8 =>$

$32$ $32$

Answer 2 · 2018-07-25T21:19:40

$32$ $32$

$4 \sqrt{16 \cdot 2} \cdot \sqrt{2} = 4 \cdot 4 \cdot \sqrt{2} \cdot \sqrt{2} = 32$ $4sqrt(16*2)*sqrt2= 4*4*sqrt2*sqrt2= 32$

How do you simplify 4sqrt32*sqrt24√32⋅√24sqrt32*sqrt2?