How do you simplify $(4x)^(1/2)*(9x)^(1/2)$ ?

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Answer 1 · 2015-06-14T19:55:56

Use the rule $x^(m/n)=root(n)(x^m)$ $; n!=0$
http://www.regentsprep.org/regents/math/algtrig/ato1/fractionalexp.htm
Solve as usual to get $6x$ .

$x^(m/n)=root(n)(x^m)$ $; n=2="square root"$ $;m=1$

$(4x)^(1/2)*(9x)^(1/2)$ =

$sqrt(4x)*sqrt(9x)$ =

$2sqrt x*3sqrtx$ =

$2*3sqrt xsqrtx$ =

$6sqrt(x^2)$ =

$6x$

How do you simplify (4x)^(1/2)*(9x)^(1/2)(4x)^(1/2)*(9x)^(1/2)?