How do you simplify $(5 + x) (3 - 2 x)$ $(5 + x)(3 - 2x)$ ?

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How do you simplify $(5 + x) (3 - 2 x)$ $(5 + x)(3 - 2x)$ ?

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Answer 1 · 2015-11-05T12:21:47

$- 2 x^{2} - 7 x + 15$ $-2x^2-7x+15$

Explanation:

To simplify to binomials you multiply each term from one set of parentheses by all the terms in the next. So...
$5 \cdot 3 = 15$ $5*3 = 15$
$5 \cdot (- 2 x) = - 10 x$ $5*(-2x) = -10x$

$x \cdot 3 = 3 x$ $x*3 = 3x$
$x \cdot (- 2 x) = - 2 x^{2}$ $x*(-2x) = -2x^2$

Then you combine all the like terms which in this case is $- 10 x$ $-10x$ and $3 x$ $3x$ leaving you with $- 2 x^{2} - 7 x + 15$ $-2x^2-7x+15$ (normally you order by the greatest coefficient)

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How do you simplify $(5 + x) (3 - 2 x)$ $(5 + x)(3 - 2x)$ ?

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How do you simplify (5 + x)(3 - 2x) (5+x)(3−2x)(5 + x)(3 - 2x) ?

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How do you simplify $(5 + x) (3 - 2 x)$ $(5 + x)(3 - 2x)$ ?