How do you simplify $- 6 + \frac{- 2 \sqrt{3}}{12}$ $-6 +(-2sqrt3)/ 12$ ?

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Answer 1 · 2018-07-05T19:52:15

$- \frac{6 \sqrt{3} + 1}{2 \sqrt{3}}$ $-{6\sqrt3+1}/{2\sqrt3 }$

$- 6 + \frac{- 2 \sqrt{3}}{12}$ $-6+{-2\sqrt3}/12$

$= - 6 - \frac{2 \sqrt{3}}{2^{2} \cdot 3}$ $=-6-{2\sqrt3}/{2^2\cdot3 }$

$= - 6 - \frac{1}{2 \sqrt{3}}$ $=-6-{1}/{2\sqrt3 }$

$= \frac{- 6 \sqrt{3} - 1}{2 \sqrt{3}}$ $={-6\sqrt3-1}/{2\sqrt3 }$

$= - \frac{6 \sqrt{3} + 1}{2 \sqrt{3}}$ $=-{6\sqrt3+1}/{2\sqrt3 }$

How do you simplify −6+−2√312-6 +(-2sqrt3)/ 12?