How do you simplify ${(6 - x^{2})}^{2}$ $(6 - x ^2)^2$ ?

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Answer 1 · 2017-06-29T13:17:22

See a solution process below:

This is a special form of a quadratic where:

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a - b)^2 = a^2 - 2ab + b^2$

Substituting:

$6$ $6$ for $a$ $a$

$x^{2}$ $x^2$ for $b$ $b$ gives:

${(6 - b)}^{2} = 6^{2} - (2 \cdot 6 \cdot x^{2}) + {(x^{2})}^{2} =$ $(6 - b)^2 = 6^2 - (2 * 6 * x^2) + (x^2)^2 =$

$36 - 12 x^{2} + x^{4}$ $36 - 12x^2 + x^4$

Or, in standard polynomial form:

$x^{4} - 12 x^{2} + 36$ $x^4 - 12x^2 + 36$

How do you simplify (6 - x ^2)^2(6−x2)2(6 - x ^2)^2?