How do you simplify ${(\frac{7^{3}}{4})}^{- \frac{2}{9}}$ $(7^3/4)^(-2/9)$ ?

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Answer 1 · 2018-04-18T02:44:01

$\Rightarrow \frac{{(7)}^{- (\frac{2}{3})}}{{(2)}^{- (\frac{4}{9})}}$ $color(brown)(=> (7)^-(2/3) / (2)^-(4/9)$

${(\frac{7^{3}}{4})}^{- (\frac{2}{9})}$ $(7^3 / 4)^(-(2/9)$

![https://www.youtube.com/watch?v=ARLS2TmFT94]( useruploads.socratic.org )

${(x^{n})}^{m} = x^{m n}$ $(x^n)^m = x^(mn)$

$\Rightarrow \frac{{(7^{3})}^{- (\frac{2}{9})}}{4^{- (\frac{2}{9})}}$ $=>(7^3)^-(2/9) / 4^-(2/9)$

$\Rightarrow \frac{{(7)}^{3 \cdot - (\frac{2}{9})}}{2^{2 \cdot - (\frac{2}{9})}}$ $=> (7)^(3 * -(2/9)) / (2^( 2 * -(2/9))$

$\Rightarrow \frac{{(7)}^{- (\frac{2}{3})}}{{(2)}^{- (\frac{4}{9})}}$ $color(brown)(=> (7)^-(2/3) / (2)^-(4/9)$

How do you simplify (734)−29(7^3/4)^(-2/9)?