How do you simplify $(9n^4)^(1/2)$ ?

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Answer 1 · 2017-04-10T06:35:34

$3n^2$

We can distribute the fractional exponent through the expression:

$(9n^4)^(1/2)=9^(1/2)xx(n^4)^(1/2)$

I'm going to rewrite $9=3^2$

$(3^2)^(1/2)xx(n^4)^(1/2)$

We can now use the rule that $(x^a)^b=x^(ab)$

$3^(2xx(1/2))xxn^(4xx(1/2))$

$3^1xxn^2=3n^2$

How do you simplify (9n^4)^(1/2)(9n^4)^(1/2)?