How do you simplify $(root3(-162x^6))$ ?

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Answer 1 · 2015-10-03T17:56:26

$root(3)(-162x^6) = x^2(-3root(3)(6))$

We can take a minus out of the root, because $-1 = (-1)^3$

$-root(3)(162x^6)$

We know that $x^6 = x^2 * x^2 * x^2$ or $x^6 = (x^2)^3$ , so we can take a $x^2$ out of the root

$-x^2root(3)(162)$

Lastly, all we have to do is factor the $162$ , so

So we can take a $3$ out of the root, leaving a $2*3$ , that is, $6$ inside it. So

$root(3)(-162x^6) = x^2(-3root(3)(6))$

How do you simplify (root3(-162x^6))(root3(-162x^6))?