How do you simplify root3 (x^6 y^7)/root3 93x6y739?

1 Answer
May 10, 2018

root(3)(x^6y^7)/root(3)93x6y739 can be written as =(xy)^2root(3)(y/9)(xy)23y9

Explanation:

You have the expression root(3)(x^6y^7)/root(3)93x6y739
Remember that the cubic root root(3)3 of something means a number which multiplied with itself three times (z*z*z)(zzz) gives the number under the root sign.

("multiplied with itself three times" is, of course, not quite precise, but I mean that n is a factor three times, i.e. z*z*zzzz.)

Let's rewrite the expression a little:

root(3)(x^6y^7)/root(3)9 = root(3)((xy)^6y/3^2)3x6y739=3(xy)6y32
=(xy)^2root(3)(y/3^2)(xy)23y32
Or if you will
=(xy)^2root(3)(y/9)(xy)23y9
depending on what you prefer.

We may be fooled to think that root(3)939 can be simplified, but it is not a cubic number. If we had had 27=3^327=33 instead, we would get the nice expression
=(xy)^2/3root(3)(y)(xy)233y