How do you simplify $Sin (pi/3 - x)-cos(pi/6 + x)$ ?

Question

9671 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-08T18:22:26

0

$sin (pi/3-x)= sin (pi/3) cos x- cos (pi/3) sinx$
= $sqrt 3/2 cos x -1/2 sinx$

$cos(pi/6+x)= cos (pi/6)cos x- sin (pi/6) sin x$

$= sqrt 3/2 cos x- 1/2 sin x$

On subtracting the answer would be 0 as both expressions are equal

How do you simplify Sin (pi/3 - x)-cos(pi/6 + x)Sin (pi/3 - x)-cos(pi/6 + x)?