How do you simplify sqrt(135b^2c^3d) • sqrt(5b^2d)√135b2c3d∙√5b2d? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Martin C. Mar 22, 2018 15b^2cdsqrt(3c)15b2cd√3c Explanation: sqrt(135b^2c^3d) * sqrt(5b^2d)=sqrt(5*5c^2d^2b^4*27c)√135b2c3d⋅√5b2d=√5⋅5c2d2b4⋅27c =5*b^2cd*sqrt(27c)=5*b^2cd*sqrt(3*3*3c)=15b^2cdsqrt(3c)=5⋅b2cd⋅√27c=5⋅b2cd⋅√3⋅3⋅3c=15b2cd√3c Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 1632 views around the world You can reuse this answer Creative Commons License