How do you simplify $sqrt( 14-a) =sqrt( a+3) +3$ ?

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Answer 1 · 2017-04-05T14:02:45

I have taken you step by step to a point where you may take over.
A lot of detail is given.

Square both sides

$14-a=(a+3)+6sqrt(a+3)+9$

Subtract $(a+3)$ from both sides

$11-2a=6sqrt(a+3)+9$

Subtract 9 from both sides

$2-2a=6sqrt(a+3)$

Divide both sides by 6

$1/3-a/3=sqrt(a+3)$

Square both sides

$1/9-2/3(a/3)+a^2/9=a+3$

$-26/9-(2a)/9-(9a)/9+a^2/9=0$

$-26/9-(11a)/9+a^2/9=0$

$-26-11a+a^2=0$

How do you simplify sqrt( 14-a) =sqrt( a+3) +3sqrt( 14-a) =sqrt( a+3) +3?