How do you simplify $sqrt(2x ) div sqrt(9x)$ ?

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Answer 1 · 2015-09-20T20:04:34

$sqrt2/3$

Rewrite in fractional form:
$sqrt(2x) -: sqrt(9x) = sqrt(2x)/sqrt(9x)$

Remember the rule:
$sqrt(ab)=sqrt(a)sqrt(b)$

so breaking down the roots, we get:
$= (sqrt(2)sqrt(x))/(sqrt(9)sqrt(x))$

Now, $sqrt(x)/sqrt(x)=1$ so that's gone, and $sqrt(9)=3$ , so we end up having:
$= sqrt2/3$

How do you simplify sqrt(2x ) div sqrt(9x)sqrt(2x ) div sqrt(9x)?