How do you simplify $\sqrt{3 y - 2} = y$ $sqrt(3y-2 ) = y$ ?

Question

1888 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-04T21:05:35

$y = 1$ $y=1$ or $y = 2$ $y=2$

$\sqrt{3 y - 2} = y$ $sqrt(3y-2)=y$

$\Rightarrow 3 y - 2 = y^{2}$ $rArr 3y-2=y^2$

#rArr y^2-3y-2=0

$\Rightarrow (y - 2) (y - 1) = 0$ $rArr(y-2)(y-1)=0$

$\Rightarrow y - 2 = 0$ $rArr y-2=0$ or $y - 1 = 0$ $y-1=0$

$\Rightarrow y = 2$ $rArr y=2$ or $y = 1$ $y=1$

We now check both solutions

$\sqrt{3 (2) - 2} = 2$ $sqrt(3(2)-2)=2$

$\sqrt{3 (1) - 2} = 1$ $sqrt(3(1)-2)=1$

So both solutions are valid.

How do you simplify √3y−2=ysqrt(3y-2 ) = y?