How do you solve $\sqrt{5 x + 9} + 3 = 2 x$ $sqrt( 5x+9) + 3 = 2x$ ?

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Answer 1 · 2016-08-03T02:06:00

$\sqrt{5 x + 9} = 2 x - 3$ $sqrt(5x + 9) = 2x - 3$

${(\sqrt{5 x + 9})}^{2} = {(2 x - 3)}^{2}$ $(sqrt(5x + 9))^2 = (2x - 3)^2$

$5 x + 9 = 4 x^{2} - 12 x + 9$ $5x + 9 = 4x^2 - 12x + 9$

$0 = 4 x^{2} - 17 x$ $0 = 4x^2 - 17x$

$0 = x (4 x - 17)$ $0 = x(4x - 17)$

$x = 0 and \frac{17}{4}$ $x = 0 and 17/4$

Checking in the original equation we find the $x = 0$ $x = 0$ is extraneous. Hence, the solution set is ${\frac{17}{4}}$ ${17/4}$ .

Hopefully this helps!

How do you solve sqrt( 5x+9) + 3 = 2x√5x+9+3=2xsqrt( 5x+9) + 3 = 2x?