How do you simplify $(\sqrt{7} + \sqrt{2}) (2 \sqrt{7} - 3 \sqrt{2})$ $(sqrt(7) + sqrt(2))(2sqrt(7)-3sqrt(2))$ ?

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Answer 1 · 2018-04-05T19:45:25

$2 - \sqrt{14}$ $2 - sqrt14$

Here's how I did it:

First, let's split this multiplication process up:

$\sqrt{7} \cdot 2 \sqrt{7} = 2 \cdot 7 = 14$ $sqrt7 * 2sqrt7 = 2 * 7 = 14$

$\sqrt{7} \cdot - 3 \sqrt{2} = - 3 \sqrt{14}$ $sqrt7 * -3sqrt2 = -3sqrt14$

$\sqrt{2} \cdot 2 \sqrt{7} = 2 \sqrt{14}$ $sqrt2 * 2sqrt7 = 2sqrt14$

$\sqrt{2} \cdot - 3 \sqrt{2} = - 3 \cdot 4 = - 12$ $sqrt2 * -3sqrt2 = -3 * 4 = -12$

Now when we combine this all together we get:
$14 - 3 \sqrt{14} + 2 \sqrt{14} - 12$ $14 - 3sqrt14 + 2sqrt14 - 12$

We can still simplify this to:
$2 - \sqrt{14}$ $2 - sqrt14$

How do you simplify (√7+√2)(2√7−3√2)(sqrt(7) + sqrt(2))(2sqrt(7)-3sqrt(2))?