How do you simplify $(sqrt10 - 9) ^2$ ?

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Answer 1 · 2016-05-21T01:41:12

We are going to use the identity

$(A-B)^2=A^2-2*A*B+B^2$

Hence we have that

$(sqrt10-9)^2=(sqrt10)^2-2*sqrt10*9+9^2= 10-18*sqrt10+81=91-18*sqrt10$

How do you simplify (sqrt10 - 9) ^2(sqrt10 - 9) ^2?