How do you simplify $(\sqrt{3} + 4 \sqrt{5}) (2 \sqrt{3} - \sqrt{5})$ $(sqrt3+4 sqrt5)(2 sqrt3- sqrt5)$ ?

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How do you simplify $(\sqrt{3} + 4 \sqrt{5}) (2 \sqrt{3} - \sqrt{5})$ $(sqrt3+4 sqrt5)(2 sqrt3- sqrt5)$ ?

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Answer 1 · 2017-07-02T16:32:34

$= 7 \sqrt{15} - 14$ $=7sqrt15-14$

Explanation:

First we will multiply term by term and get:

$\sqrt{3} \cdot 2 \sqrt{3} - \sqrt{3} \cdot \sqrt{5} + 4 \sqrt{5} \cdot 2 \sqrt{3} - 4 \sqrt{5} \cdot \sqrt{5}$ $sqrt3*2sqrt3-sqrt3*sqrt5+4sqrt5*2sqrt3-4sqrt5*sqrt5$

$= 2 \cdot 3 - \sqrt{15} + 8 \sqrt{15} - 4 \cdot 5$ $=2*3-sqrt15+8sqrt15-4*5$

Then we will sum the like terms and get:

$= 6 + 7 \sqrt{15} - 20$ $=6+7sqrt15-20$

$= 7 \sqrt{15} - 14$ $=7sqrt15-14$

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How do you simplify $(\sqrt{3} + 4 \sqrt{5}) (2 \sqrt{3} - \sqrt{5})$ $(sqrt3+4 sqrt5)(2 sqrt3- sqrt5)$ ?

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How do you simplify (√3+4√5)(2√3−√5)(sqrt3+4 sqrt5)(2 sqrt3- sqrt5)?

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How do you simplify $(\sqrt{3} + 4 \sqrt{5}) (2 \sqrt{3} - \sqrt{5})$ $(sqrt3+4 sqrt5)(2 sqrt3- sqrt5)$ ?