How do you simplify $sqrt3(sqrt12+sqrt6)$ ?

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Answer 1 · 2016-10-24T15:57:48

$=6+3sqrt2$

Firstly multiply the brackets.

$sqrt3(sqrt12+sqrt6)=sqrt3sqrt12+sqrt3sqrt6$

$=sqrt36+sqrt18$

Now simplify the square roots.

$=6+sqrt(9xx2)=6+sqrt9sqrt2$

$=6+3sqrt2$

How do you simplify sqrt3(sqrt12+sqrt6)sqrt3(sqrt12+sqrt6)?