How do you simplify sqrt32*sqrt144? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Ratnaker Mehta Jul 1, 2016 48sqrt2. Explanation: We use prime factorisation of 32=2^5 and 144=2^4*3^2. Hence the expression, =sqrt32*sqrt144, =(2^5)^(1/2)*(2^4*3^2)^(1/2)=(2^4*2)^(1/2)*(2^4*3^2)^(1/2) ={(2^4)^(1/2)2^(1/2)}{(2^4)^(1/2)*(3^2)^(1/2)}=2^(4*1/2)*2^(1/2)*2^(4*1/2)*3^(2*1/2)=2^2*2^(1/2)*2^2*3^1=4*sqrt2*4*3=48sqrt2. Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1158 views around the world You can reuse this answer Creative Commons License