How do you simplify $\sqrt{5} \div \sqrt{3}$ $sqrt5 div sqrt3$ ?

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How do you simplify $\sqrt{5} \div \sqrt{3}$ $sqrt5 div sqrt3$ ?

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Answer 1 · 2017-06-28T19:45:46

$\frac{\sqrt{15}}{3}$ $sqrt(15)/3$

Explanation:

$\sqrt{5} \div \sqrt{3}$ $sqrt(5)-:sqrt(3)$ can be rewritten as $\frac{\sqrt{5}}{\sqrt{3}}$ $sqrt(5)/sqrt(3)$ .

As there is a surd (radical) on the botoom, we have to rationalise the denominator, to do this we use the equation: $\frac{a}{\sqrt{b}} \equiv \frac{a \cdot \sqrt{b}}{{\sqrt{b}}^{2}} = \frac{a \sqrt{b}}{b}$ $a/sqrt(b)-=(a*sqrt(b))/(sqrt(b)^2)=(asqrt(b))/b$ .

In this case, $a = \sqrt{5}$ $a=sqrt(5)$ and $b = \sqrt{3}$ $b=sqrt(3)$ . By putting our values in we get: $\frac{\sqrt{5}}{\sqrt{3}} \equiv \frac{\sqrt{5} \cdot \sqrt{3}}{{\sqrt{3}}^{2}} = \frac{\sqrt{5 \cdot 3}}{3} = \frac{\sqrt{15}}{3}$ $sqrt(5)/sqrt(3)-=(sqrt(5)*sqrt(3))/(sqrt(3)^2)=(sqrt(5*3))/3=(sqrt(15))/3$ . As none of the factors of 15 are perfect squares, this fraction cannot be simplified.

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How do you simplify $\sqrt{5} \div \sqrt{3}$ $sqrt5 div sqrt3$ ?

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