How do you simplify $sqrt63/sqrt7$ ?

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Answer 1 · 2016-04-26T00:24:41

$sqrt(63)/sqrt(7) = 3$

Using the property that $sqrt(a)/sqrt(b) = sqrt(a/b)$ for $a>=0$ , $b>0$ :

$sqrt(63)/sqrt(7) = sqrt(63/7) = sqrt(9) = sqrt(3^2) = 3$

How do you simplify sqrt63/sqrt7sqrt63/sqrt7?