How do you simplify sqrt7(2sqrt3+3sqrt7)√7(2√3+3√7)? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Gerardina C. Feb 11, 2017 2sqrt21+212√21+21 Explanation: Since sqrta*sqrtb=sqrt(ab)√a⋅√b=√ab and sqrta*sqrta=a√a⋅√a=a, the given expression is: 2sqrt21+3*7=2√21+3⋅7= =2sqrt21+21=2√21+21 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}2√3? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)73√5? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))(√a+√b)(√a−√b)? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}2x√5x? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)√5√15? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))(7√13+2√6)(2√3+3√6)? See all questions in Multiplication and Division of Radicals Impact of this question 994 views around the world You can reuse this answer Creative Commons License