How do you simplify $\sqrt{7} \cdot \sqrt{7}$ $sqrt7*sqrt7$ ?

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Answer 1 · 2017-10-20T19:03:57

$7$ $7$

Use properties of square roots first:

$\sqrt{7} \cdot \sqrt{7} = \sqrt{7 \cdot 7}$ $sqrt(7)*sqrt(7)=sqrt(7*7)$

Then simplify within the square root:

$\sqrt{7 \cdot 7} = \sqrt{49}$ $sqrt(7*7)=sqrt(49)$

Then take the square root of $49$ $49$ (what number times itself is $49$ $49$ ?):

$\sqrt{49} = 7$ $sqrt(49)=7$

How do you simplify sqrt7*sqrt7√7⋅√7sqrt7*sqrt7?