How do you simplify the expression $\sqrt{\frac{2}{3}} + \sqrt{6}$ $sqrt(2/3)+sqrt6$ ?

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Answer 1 · 2017-10-11T04:10:43

$4 \sqrt{\frac{2}{3}}$ $4sqrt(2/3)$

I can rewrite the second term in the expression like so:

$\sqrt{\frac{2}{3}} + \sqrt{\frac{18}{3}}$ $sqrt(2/3)+sqrt(18/3)$

Then factor out a $\frac{2}{3}$ $2/3$ :

$\sqrt{\frac{2}{3}} + \sqrt{9 \cdot \frac{2}{3}}$ $sqrt(2/3)+sqrt(9*2/3)$

Use properties of square roots:

$\sqrt{\frac{2}{3}} + \sqrt{9} \cdot \sqrt{\frac{2}{3}}$ $sqrt(2/3)+sqrt(9)*sqrt(2/3)$

Take the square root of $9$ $9$ :

$1 \sqrt{\frac{2}{3}} + 3 \sqrt{\frac{2}{3}}$ $1sqrt(2/3)+3sqrt(2/3)$

Add like radicals:

$4 \sqrt{\frac{2}{3}}$ $4sqrt(2/3)$

How do you simplify the expression sqrt(2/3)+sqrt6√23+√6sqrt(2/3)+sqrt6?