How do you simplify the expression ${(\sqrt{2} + \sqrt{3})}^{2}$ $(sqrt2+sqrt3)^2$ ?

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Answer 1 · 2017-02-08T00:48:31

You work out the expression ${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $(a+b)^2=a^2+2ab+b^2$

$= {\sqrt{2}}^{2} + 2 \cdot \sqrt{2} \cdot \sqrt{3} + {\sqrt{3}}^{2}$ $=sqrt2^2+2*sqrt2*sqrt3+sqrt3^2$

$= 2 + 2 \cdot \sqrt{2 \cdot 3} + 3$ $=2+2*sqrt(2*3)+3$

$= 5 + 2 \sqrt{6}$ $=5+2sqrt6$

How do you simplify the expression (sqrt2+sqrt3)^2(√2+√3)2(sqrt2+sqrt3)^2?