How do you simplify the radical expression $\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ $(3-sqrt2)/(3 +sqrt2)$ ?

Question

How do you simplify the radical expression $\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ $(3-sqrt2)/(3 +sqrt2)$ ?

1 Answer

Impact of this question

1597 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-06T21:37:44

Method: Rationalize the denominator

$\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ $(3 - sqrt(2))/(3 + sqrt(2))$ becomes $\frac{(3 - \sqrt{2}) (3 - \sqrt{2})}{(3 + \sqrt{2}) (3 - \sqrt{2})}$ $((3 - sqrt(2))(3 - sqrt(2)))/((3 + sqrt(2))(3 - sqrt(2)))$

$\Rightarrow \frac{9 - 2 (3 \sqrt{2}) + 2}{9 - (2)}$ $=> (9 - 2(3sqrt(2)) + 2)/(9 - (2))$

$\Rightarrow \frac{11 - 6 \sqrt{2}}{7}$ $=> (11 - 6sqrt(2))/7$

Science

Math

Humanities

... and beyond

How do you simplify the radical expression $\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ $(3-sqrt2)/(3 +sqrt2)$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you simplify the radical expression 3−√23+√2(3-sqrt2)/(3 +sqrt2)?

1 Answer

Related questions

Impact of this question

How do you simplify the radical expression $\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ $(3-sqrt2)/(3 +sqrt2)$ ?