How do you simplify $x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}}$ $x^(1/3) * x^(1/3)* x^(1/3)$ ?

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How do you simplify $x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}}$ $x^(1/3) * x^(1/3)* x^(1/3)$ ?

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Answer 1 · 2015-06-15T15:21:33

$x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} = x$ $x^(1/3)*x^(1/3)*x^(1/3) = x$

Explanation:

Since $b^{m} \cdot b^{n} \cdot b^{p} = b^{m + n + p}$ $b^m*b^n*b^p = b^(m+n+p)$

$x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} = x^{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}} = x^{1} = x$ $x^(1/3)*x^(1/3)*x^(1/3) = x^(1/3+1/3+1/3) = x^1 = x$

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How do you simplify $x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}}$ $x^(1/3) * x^(1/3)* x^(1/3)$ ?

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How do you simplify $x^{\frac{1}{3}} \cdot x^{\frac{1}{3}} \cdot x^{\frac{1}{3}}$ $x^(1/3) * x^(1/3)* x^(1/3)$ ?