How do you simplify $x^{\frac{1}{3}} \cdot x^{\frac{1}{5}}$ $x^(1/3)*x^(1/5)$ ?

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Answer 1 · 2016-10-13T18:08:50

$x^{\frac{8}{15}}$ $x ^(8/15)$

When you multiply with exponents it is necessary to add the exponents of any like bases

$x^{2} \times x^{2}$ $x^2 xx x^2$ = $x^{2 + 2} = x^{4}$ $x^(2+2) = x^4$

So it is necessary to add $\frac{1}{3} + \frac{1}{5}$ $1/3+ 1/5$ Find a common denominator

for $\frac{1}{3}$ $1/3$ and $\frac{1}{5}$ $1/5$ The common denominator is 15.

multiply $\frac{1}{3} \times \frac{5}{5} = \frac{5}{15}$ $1/3 xx 5/5 = 5/15$

multiply $\frac{1}{5} \times \frac{3}{3} = \frac{3}{15}$ $1/5 xx 3/3 = 3/15$ add the two fractions.

             total            =    #8/15#

$x^{\frac{1}{3}} \times x^{\frac{1}{5}} = x^{\frac{1}{3} + \frac{1}{5}}$ $x^(1/3) xx x^(1/5) = x^(1/3+1/5)$

= $x^{\frac{8}{15}}$ $x^(8/15)$

How do you simplify x^(1/3)*x^(1/5)x13⋅x15x^(1/3)*x^(1/5)?