How do you simplify $[\frac{X - 1}{X - 3}] = [\frac{2}{X - 3}]$ $[(X-1) / (X-3)] = [2 /(X-3)]$ ?

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Answer 1 · 2015-10-30T23:52:54

Subtract $\frac{2}{X - 3}$ $2/(X-3)$ from both sides to get:

$\frac{X - 3}{X - 3} = 0$ $(X-3)/(X-3) = 0$

or $1 = 0$ $1 = 0$ with exclusion $x \neq 3$ $x != 3$

which is an equation with no solutions.

$\frac{X - 1}{X - 3} - \frac{2}{X - 3} = \frac{(X - 1) - 2}{X - 3} = \frac{X - 3}{X - 3}$ $(X-1)/(X-3) - 2/(X-3) = ((X-1)-2)/(X-3) = (X-3)/(X-3$

How do you simplify [(X-1) / (X-3)] = [2 /(X-3)][X−1X−3]=[2X−3][(X-1) / (X-3)] = [2 /(X-3)]?