How do you simplify $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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How do you simplify $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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Answer 1 · 2016-07-04T18:11:55

$x^{\frac{11}{12}} - x^{\frac{5}{3}}$ $x^(11/12) - x^(5/3)$

Explanation:

Follow the normal method of the distributive law, but there are indices to consider as well.

If the bases are the same, then add the indices when multiplying.

$x^{\frac{2}{3}} \times x^{\frac{1}{4}} - x^{\frac{2}{3}} \times x^{1}$ $x^(2/3) xx x^(1/4) - x^(2/3) xx x^1$

$x^{\frac{11}{12}} - x^{\frac{5}{3}} \frac{8 + 3}{12} = \frac{11}{12}$ $x^(11/12) - x^(5/3)" " (8+3)/12 = 11/12$

One might consider taking out a common factor of $x^{\frac{11}{12}}$ $x^(11/12)$
but this would not produce an answer that can be simplified further anyway.

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How do you simplify $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?

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How do you simplify $x^{\frac{2}{3}} (x^{\frac{1}{4}} - x)$ $x^(2/3)(x^(1/4) - x)$ ?