How do you simplify $[x^{\frac{2}{9}} - 5] [x^{\frac{2}{9}} + 1]$ $[x^(2/9) - 5] [x^(2/9) + 1]$ ?

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How do you simplify $[x^{\frac{2}{9}} - 5] [x^{\frac{2}{9}} + 1]$ $[x^(2/9) - 5] [x^(2/9) + 1]$ ?

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Answer 1 · 2015-04-08T18:23:12

You have:
$(x^{\frac{2}{9}} - 5) (x^{\frac{2}{9}} + 1) =$ $(x^(2/9)-5)(x^(2/9)+1)=$
$= x^{\frac{2}{9} + \frac{2}{9}} + x^{\frac{2}{9}} - 5 x^{\frac{2}{9}} - 5 =$ $=x^(2/9+2/9)+x^(2/9)-5x^(2/9)-5=$
$x^{\frac{4}{9}} - 4 x^{\frac{2}{9}} - 5$ $x^(4/9)-4x^(2/9)-5$

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How do you simplify $[x^{\frac{2}{9}} - 5] [x^{\frac{2}{9}} + 1]$ $[x^(2/9) - 5] [x^(2/9) + 1]$ ?

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