How do you simplify $x^(3/7)/x^(1/3)$ ?

Question

2002 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-24T16:43:18

$x^(2/21)$

"If you are dividing and the bases are the same, subtract the indices."

Consider: $x^8/x^3 = x^(8-3) = x^5$

In the same way:

$(x^(3/7))/(x^(1/3)) = x^(3/7-1/3)$

Working with the fractions: find the LCD

$3/7-1/3 = (9-7)/21 = 2/21$

$x^(3/7-1/3)= x^(2/21)$

Answer 2 · 2017-03-24T16:50:56

$x^(2/21)$

We know, a = $1/a^-1. So, 1/x^(1/3)= x^(-1/3)$

Thereby $x^(3/7) /x^(1/3) = x^(3/7). x^(-1/3) = x ^(3/7-1/3)$

$rArr x^[(9-7)/21] = x^(2/21)$

How do you simplify x^(3/7)/x^(1/3)x^(3/7)/x^(1/3)?