How do you solve $\frac{1}{2} (3 x - 8) + 4 = 2 x - (5 x + 1)$ $1/2(3x-8)+4 = 2x-(5x+1)$ ?

Question

How do you solve $\frac{1}{2} (3 x - 8) + 4 = 2 x - (5 x + 1)$ $1/2(3x-8)+4 = 2x-(5x+1)$ ?

1 Answer

Impact of this question

1808 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-23T15:34:35

$x = - \frac{26}{9}$ $x=-26/9$

Explanation:

$\frac{3}{2} x + 4 + 4 = 2 x - 5 x - 5$ $3/2x+4+4=2x-5x-5$ distribute
$\frac{3}{2} x + 8 = - 3 x - 5$ $3/2x+8=-3x-5$ combine like terms
$3 x + 16 = - 6 x - 10$ $3x+16=-6x-10$ multiply whole equation by 2 to get rid of fraction
$9 x = - 26$ $9x=-26$
$x = - \frac{26}{9}$ $x=-26/9$

Science

Math

Humanities

... and beyond

How do you solve $\frac{1}{2} (3 x - 8) + 4 = 2 x - (5 x + 1)$ $1/2(3x-8)+4 = 2x-(5x+1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 1/2(3x-8)+4 = 2x-(5x+1)12(3x−8)+4=2x−(5x+1)1/2(3x-8)+4 = 2x-(5x+1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $\frac{1}{2} (3 x - 8) + 4 = 2 x - (5 x + 1)$ $1/2(3x-8)+4 = 2x-(5x+1)$ ?