How do you solve $- \frac{1}{2} x^{\frac{1}{5}} = 10$ $-1/2x^(1/5)=10$ ?

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Answer 1 · 2016-08-08T12:44:29

$x = {(- 20)}^{5} = - 3, 200, 000$ $x =(-20)^5= -3,200,000$

$- \frac{1}{2} x^{\frac{1}{5}} = 10 isolate the term in x$ $-1/2x^(1/5)=10" isolate the term in x"$

$- 2 \times - \frac{1}{2} x^{\frac{1}{5}} = - 2 \times 10$ $color(red)(-2xx)-1/2x^(1/5)=color(red)(-2xx)10$

$x^{\frac{1}{5}} = - 20 raise to the power 5$ $x^(1/5) = -20" raise to the power 5"$

${(x^{\frac{1}{5}})}^{5} = {(- 20)}^{5}$ $(x^(1/5))^color(blue)5 = (-20)^color(blue)5$

$x = - 3, 200, 000$ $x = -3,200,000$

How do you solve -1/2x^(1/5)=10−12x15=10-1/2x^(1/5)=10?