How do you solve $1/8+2/t=17/(8t)$ ?

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Answer 1 · 2015-10-16T10:47:23

$t=1$ .

First of all, write the left member as

$1/8+2/t = (t+2*8)/(8t) = (t+16)/(8t)$

(note that $t$ must not be zero, otherwise we would have $0$ at the denominator).

So we have

$(t+16)/(8t) = 17/(8t)$

since the denominators are equal, the equation holds if and only if the numerators are equal. This means

$t+16=17$ . Solving for $t$ , we get $t=17-16=1$ .

CHECK: for $t=1$ , the equation becomes

$1/8+2=17/8$ , which is indeed true.

How do you solve 1/8+2/t=17/(8t)1/8+2/t=17/(8t)?