How do you solve $1/(c-2) + 1/c = 2/(c(c-2))$ ?

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Answer 1 · 2015-12-15T13:51:37

No solution

Assume that solution exist.

Multiply both sides by $c(c-2)$ .

$c+(c-2)=2$

$2c-2=2$

$2c=4$

$c=2$

Upon inspection, there is division by zero in the first fraction.

Hence there are no solution.

How do you solve 1/(c-2) + 1/c = 2/(c(c-2))1/(c-2) + 1/c = 2/(c(c-2))?