How do you solve $1/(x-6) + 1/(x-2)= 6/5$ ?

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Answer 1 · 2017-10-07T11:28:14

Solution : $x =7 ,x= 8/3$

$1/(x-6) +1/(x-2) = 6/5$ . Multiplying by $5(x-6)(x-2)$ on both

sides we get $5(x-2)+5(x-6)=6(x-6)(x-2)$ or

$5x-10+5x-30=6(x^2-8x+12)$ or

$10x-40= 6x^2-48x+72$ or

$6x^2-48x+72-10x+40=0 or 6x^2-58x+112 =0$ or

$3x^2-29x+56 =0 or 3x^2-21x -8x+56 =0$ or

$3x(x-7)-8(x-7) =0 or (x-7)(3x-8) =0$

$:. x =7 ,x= 8/3 :.$ Solution : $x =7 ,x= 8/3$ [Ans]

How do you solve 1/(x-6) + 1/(x-2)= 6/5 1/(x-6) + 1/(x-2)= 6/5 ?