How do you solve $10 + 2/3t=6$ ?

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Answer 1 · 2017-07-01T03:58:13

$-6$

To isolate $t$ , you must first subtract 10 from both sides of the equation:
$10+t2/3-10=6-10$
$2/3t=-4$

Then, to cancel out the effect of the $2/3$ on the $t$ , you can multiply both sides by the recipricol of 2/3 which is 3/2

$(2/3*3/2)t=-4*3/2$
$t=-12/2$
$t=-6$

How do you solve 10 + 2/3t=610 + 2/3t=6?