How do you solve $12 - 4 x = 16$ ?

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Answer 1 · 2016-02-14T11:02:52

$x=-1$

$12-4x=16$

Subtract $12$ both sides:

$rarr-4x=16-12$

$rarr-4x=4$

Divide both sides by $4$

$rarr(-cancel4x)/cancel4=cancel4/cancel4$

$rarr-x=1$

$rArrx=-1$

How do you solve 12 - 4 x = 1612 - 4 x = 16?